- Location
- UK
I would like to propose that there is an equation in which the amount of Kongou needed to erode sanity is as such.
Coef. of sanity= 1^1/(Kt/K)+((tKI*qKI)/KI)
Or, in English,
The coeficent of sanity is one to the power time exposed to Kongou divided by the number of Kongou are in the area plus the time exposed to Kongou Impersonators times the quality of the Kongou Impersonators divided by the number of Kongou Impersonators.
Now, if the number of Kongous and Kongou Impersonators are 0, then the coeficent of sanity is therefore 1, and total sanity is maintained. If there are no Knogou-class in the area but there are Kongou Impersonators, there is still a slight drain on sanity, however the ammount of sanity drain as exposed to Kongou Impersonators falls off sharply with incresing numbers as the sheer confusion and disbelief of there being so many Kongou in the area forms a protective shield over some infinetly tiny chunk of sanity.
EDIT: Fixed equation
You will have to fix the equation again, since 0/0 will not work. And it still seems you are raising 1 to the power of 1/(Kt/K)+((tKI*qKI)/KI), if we assume everything to the right of ^ is brackets. And even then, precedence of operators would cause some issues.