Army of Liberty: a Fantasy Revolutionary Warfare Quest

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Our allied general actually has orders to be on the offensive though.

I'd rather we secure the south of the river and dig in. Our sector is expected to be the main area of conflict, and I want to face the Nornish regular army with the advantage of fortifications and the enemy having to do a river crossing.
Well, the big issue there is the number of army actions we would be missing out on and the issue of getting the 5th to keep up with us. We don't get many army actions for reorganization there. River crossings are quite bad for the enemy, but attacking fortified hilly terrain with us knowing the local terrain is also a disadvantage. Getting more units and higher drill is also a strong advantage, we lack a strong ability to counterattack at the moment.
 
We have 4 Cavalry, 2 of them behind his artillery, he has 1 Cavalry.
He has 4 cavalry as well. Yes, 3 of them will be Routing, most likely, giving us a window of opportunity, but his cavalry will come back into the fight at some point.

Also, at least one of Guillory's Hussars may very well Rout if we get a bit unlucky here.
If he does not retreat, then the next turn we kill his entire Artillery Corps except the horse artillery

and I mean that literally, we will be able to do that and he cant stop us from doing that no matter what he decides to do.
No we literally cannot do that. The 10th survived a cavalry charge, why could his artillery not do the same? He can actually afford to lose a few batteries if that means we lose our cavalry. What could end up happening is a mirror of last turn where we hurt his artillery seriously, but are ultimately repulsed and lose our cavalry screen.
 
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He has 4 cavalry as well. Yes, 3 of them will be Routing, most likely, giving us a window of opportunity, but his cavalry will come back into the fight at some point.

Also, at least one of Guillory's Hussars may very well Rout if we get a bit unlucky here.

Yeah, but his cavalry are out of the fight during the next two turns. How do you think he will hold out for 2 turns without losing?

That is quite unlikely. We would need to lose the 80% chance to kill his artillery and, cause routing the hussars at +9 is not happening.

Then if we do lose that roll, we would need to have very high casualties to trigger enough morale rolls, cause +5 stress is very tanky.

No we literally cannot do that. The 10th survived a cavalry charge, why could his artillery not do the same? He can actually afford to lose a few batteries if that means we lose our cavalry, what could end up happening is a mirror of last turn where we hurt his artillery seriously, but are ultimately repulsed and lose our cavalry screen.

The 10th had -30 on every defense roll. Guillory would be hitting at 0 modifier and we are also able to do two attacks on the artillery.

also once artillery loses more than 20 it prety much gets rendered useless except for close range shots

Once we kill a few artillery our artillery also cannot rout. If we kill a few artillery momentum is at like +15, our cavalry will die before routing then.

and we had multiple units that could kill his charging cavalry, but he doesnt, he has 3 infantry and 1 cavalry in the north, and infantry is unable to catch cavalry, especially if they are also supposed to stop our rotholz infantry from charging in
 
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That is quite unlikely. We would need to lose the 80% chance to kill his artillery and, cause routing the hussars at +9 is not happening.
Here you are assuming +9 Momentum. We are not there yet, currently it is at 0.
Yeah, but his cavalry are out of the fight during the next two turns. How do you think he will hold out for 2 turns without losing?
Most likely he will lose. But I would not call it a certainty.
The 10th had -30 on every defense roll. Guillory would be hitting at 0 modifier and we are also able to do two attacks on the artillery.
0 modifier? How do you figure? His artillery seems to have modifiers ranging from 0 to +30. Only one of them has a 0 modifier?
 
Here you are assuming +9 Momentum. We are not there yet, currently it is at 0.

I am saying that there is a 80% chance we have 9 momentum in my plan, cause we kill the artillery, I guarantee all the other routs in my plan too, with what you call too much guarantee. But it gives me the certainty to plan with the momentum :)

Most likely he will lose. But I would not call it a certainty.

I would, it is a certainty, it is impossible for him to win unless we mess up or theres is a one in a million misfortune where eery roll is super bad

0 modifier? How do you figure? His artillery seems to have modifiers ra ging from 0 to +30. Only one of them has a 0 modifier?

The +30 modifiers wont be charged by our cavalry, thats the horse artillery and the 28th.

I didnt realise that most of his aritllery is at +10, but a charge+attack still mostly kill them.

and keep in mind, even if it doesnt actually kill them, killing 30 people still means the aritllery isnt able to really do anything with their combat modifier at -20
 
Haven't we spent the last two turns talking about how much momentum we'll have after the round is done only to find ourselves only just breaking even once unexpected enemy action was taken into account?
 
Haven't we spent the last two turns talking about how much momentum we'll have after the round is done only to find ourselves only just breaking even once unexpected enemy action was taken into account?

I dont know, ive not been paying attention to the last turns.

But the momentum im talking about is the momentum we have on von Trothas turn, which cant be influenced by unexcpected enemy action, cuase there isnt enemy action thats happening.

The momentum can absolutely swing in our favour, espceially with pinnipeds plan where the 8th could kill an artillery and its a 50/50 to kill the artillery, but he still has 4-5 momentum pretty much guaranteed.

In my plan it can swing around a bit too, not sure if we can get to neutral but something like +1 or +2 is possible. But at that point it doesnt matter, cause well be focusing on killing artillery, where momentum doesnt matter
 
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