Sorry about that. The point still stands: using wires to transfer that much power should be pretty much impossible.
I can't, for many reasons. One of them is waste heat and ability to transfer energy out of the reactor. Fusion reactors generate energy in the form of heat that's converted to electricity. Even if you go with direct electricity generation (possible), it'll still melt the whole ship to slag. Leaving that aside, again, you are completely neglecting mass effect. Which is used to make accelerators possible. It might be that I am an engineer, but the point is: 80 TW of power is an insane number. It requires clarke tech to handle.Not really. I'll admit I don't know the first thing about fusion technology however it's important to remember that not only did they shrink fusion technology to the point it fit on spaceships they, from what I understand, did it before they found Mass Effect technology.
So I can absolutely see them having 80TW of power generation in combat.
This is all good and nice. But now we have to calculate the heat fluxes. The Surface area of the Everest in you calculations is 2*(900*207+900*36+207*36)=452304 m^2. Let's say that due to radiators and such the working surface area is 10 times that. Now, assuming it's a perfectly black body, which means it emits as much energy as possible, and that the temperature of the hull is 800 K (a little over 500 C, a very generous assumtion), the power radiated by the ship into space would be 1.05*10^11 watts, or 105 gigawatts. This gives us aт energy conversion efficiency, i.e. how big a portion of the output of the reactors can be waste heat. At 80 TW of useful output, which is 8*10^13 watts, we have 1*10^11 of waste power, meaning that ECE is = 0.999. Which is insane. That's leaving aside how I said the temperature of the hull is 800 K, wherein it's likely to be lower.Our 40TW reactor is 8,000 times more powerful then our standard Arc Reactor. So assuming it scales by volume, which the number seems to imply, that's form an Arc Reactor 2m to 3m in diameter.
Lets assume for arguments sake that the front of the Everast is 10m by 10m (which seems really small in comparison) by 888 (size of the main gun, the actual ship would be bigger) that gives her a total volume of 88,800 cubic meters.
If we assume that 5% of the ship's volume is spent on the reactor(s), reasonable in my opinion given that it's basically a ship built to fire the main gun, that gives a volume of 4,400 cubic meters.
The 40TW arc reactor, assuming a perfect sphere which it isn't, has a volume of 113 cubic meters. Double that for two reactors and it's 226 cubic meters.
That makes the Arc Reactor 19.46 times more size efficient and that's assuming a really narrow ship. Especially since they mention that on the Kilamanjaro the broadsides are 40% of the ships width.
So lets say we up use the Nimitz as the scale. A Nimitz class is 332.8m long, 76.8 m wide and 12.5m high. That's a ratio of 23% width-to-length and 4% height-to-length.
If we assume that the Everest is 900m, 888m is the length of the accelerator after all, that gives a width of 207m and a height of 36m for a total volume of 6,706,800 and a Reactor volume of 335,340 cubic meters or 1,484 times larger then the equivalent in Arc Reactor.
That's plasma volume. It's not the size of the reactor. It's the volume of the plasma inside the vacuum chamber of the reactor. ITER itself (the whole reactor) is somewhere between 3 and 10 times as big by volume (don't remember numbers). And that's just the reactor, not the supporting equipment.As a side note ITER is, apparently anyway, 840 cubic meters so a thousand times that is 840,000 cubic meters. ~260 years andSpace MagicEezo is more then enough to justify a top of the line military reactor been 40% the size.
What I'm driving at is that there's absolutely no way, no how, from any viewpoint, that Mass Effect played at this power levels. They used mass effect fields in their accelerators, lowering the output required by many orders of magnitudes (about 3 I would say, maybe even more).