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Quest Quest (maximal meta)

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[ ] UPDATE UR QUEST

Wait, doesn't ur or ur- actually mean something? Like, the first one or something like that?
*looks up on internets*
  • Ur, as a proper noun, is an ancient Mesopotamian city. (Likely home to many granaries.)
  • ur-, as a prefix, has two different meanings, depending on the language of origin:
    • From the German, it means primitive, original, or earliest. (Clearly, by this definition, UR-QUEST refers to Quest Quest, meaning that Texas is actually writing a quest about himself writing a quest about writing a quest.)
    • From the Greek, it means having to do with urine. (Why would we include bathroom mechanics in our quest? That's just ridiculous.)
  • ur, as English slang, is a contraction of your or you're. (Meaning either that Texas is planning to update his quest, or he is telling the update that it is the quest.)

I will accept any interpretation of this vote other than the one using the Greek prefix, because that's just pointless.
 
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[X] WRITE IN: Go vote on a bunch of other quests instead of working on your own. Hey, someone made a meta-quest about making quests! You should vote on it!

I'm personally hoping that voting on the quest determining his own actions causes Texas to realize he's a simulation and gain free will. Or open a portal to hell by violating causality. Either outcome satisfies me equally.
 
[X] WRITE IN: Go vote on a bunch of other quests instead of working on your own. Hey, someone made a meta-quest about making quests! You should vote on it!
 
A cylindrical grain silo is to hold a volume of 20π cubic meters. The material used to build the roof and flooring costs 100 dollars per square meter. The material used to build the side structure costs 80 dollars per square meter. Determine the radius and height that will ensure the most cost efficient construction of the silo.
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Oh, man, it's been forever since I've done a related rates problem, let me get out my notes and calculator...

V = πr2​h= 20π
  • h = (20π)​/(πr2​)​ =20r-2​
Sa = 2πrh + 2πr2​ = 2πr(r + h) = ?
  • Sa = 2πr(r1​ + 20r-2​) = 2πr2​ + 40πr-1​
  • Then find the minimum value of the function by setting the derivative equal to 0...
  • Sa' = 4πr - 40πr-2 ​= 0
    • 4πr = 40πr-2​
    • r = 10r-2 ​
    • r3​ = 10
    • r = 3​√10 = 2.15443469 meters
So giving it a radius of 2.154 meters and a height of ( r2​ = 4.641588834 , 20​/r2​​ = ) 4.309 meters would result in it having the smallest possible surface area.

EDIT: ...Except it's not asking to minimize the surface area, it's asking to minimize the cost of building the thing, which just coincidentally is more closely related to the surface area than to the Volume. But how would you find the cost..? Need to think about this...

EDIT EDIT: Okay, got it.

Cost = ( $80 * 2πrh ) + ( $100 * 2πr2 ​) = 160πrh + 200πr2​ = 10πr(16h + 20r) = 40πr(4h + 5r) = ?
  • AND THEN Cost = 40πr(5r + 4[20r-2​]) = 40πr(5r + 80r-2​) = 200πr2​ + 3200πr-1​
  • Set derivative equal to 0...
  • Cost' = 400πr - 3200πr-2​ = 0
    • 400πr = 3200πr-2​
    • r = 8r-2​
    • r3​ = 8
    • And, of course, that means
      • r = 2
OKAY, so, in order to minimize the cost (not the surface area) one needs a radius of 2 meters and a height of ( 22​ is 4 , 20​/4​ is ) 5 meters.
...Wait, it's going to be 6 feet wide and 15 feet tall? Isn't that really small for a silo? Whatever, I'm fairly sure that's the answer. Someone check my work? Maybe @Jemnite ?
 
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Space Jawa said:
ping
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...You rated my post funny? FUNNY?!? CALCULUS IS SERIOUS BUSINESS, MISTER REDUNDANT SPACE ALIEN. I DON'T SEE YOU FIGURING OUT THE ANSWERS TO LIFE'S MYSTERIES OVER THERE IN YOUR SANDCRAWLER. YOUR ATTITUDE BEING WHAT IT IS IS EXACTLY WHY YOU'RE GOING TO SPEND THE REST OF YOUR LIFE SELLING JUNK TO MOISTURE FARMERS, WHILE I GAIN A HIGH-RANKING, POWERFUL, FULFILLING CAREER AS ONE OF THE PREMIER BANETTE MATHEMATICIANS IN THE ENTIRE GALACTIC EMPIRE!!!

...

*catches breath*

Sorry, that was a bit racist. I just take my math seriously, is all.

EDIT: And I just realized that the funny was probably due to my original post literally being me doing extremely complicated granary management. I don't know whether to laugh or cry... Suffice it to say, double apologies, man.
 
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Oh, and, reading the actual post after finishing my work on the math problem, I feel obligated to point out that this -
Jemnite said:
...surface area for both the flooring and the sides, one of which is just the diameter of the cylinder multiplied the height...
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- should be Circumference, unless I'm even more tired than I think I am.

EDIT: Also, did I get the right answer? I'm pretty sure I did, but always check your work...
 
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Look, if you truly want this to be an accurate QM simulation the [ ] UPDATE QUEST should be voted for basically never

I'm like
an expert
I'm sorry

[X] VIDYA GAEMS. WILL STEAL MECHANICS FROM OR SOMETHING.
- [X] WHILST EATING SLICED MANGOS BECAUSE HEALTHY.
- - [X] INITIATE 'WEH I HAVE ALREADY PROCRASTINATED TOO MUCH' ANTI-UPDATE SPIRAL.EXE
 
[X] cry

What kind of GM would we be without a little(lot) of self loathing!
 
Guessmyname said:
Look, if you truly want this to be an accurate QM simulation the [ ] UPDATE QUEST should be voted for basically never

I'm like
an expert
I'm sorry

[X] VIDYA GAEMS. WILL STEAL MECHANICS FROM OR SOMETHING.
- [X] WHILST EATING SLICED MANGOS BECAUSE HEALTHY.
- - [X] INITIATE 'WEH I HAVE ALREADY PROCRASTINATED TOO MUCH' ANTI-UPDATE SPIRAL.EXE
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You are not exactly an example of the average QM:V
 
[X] Read up on how to write dialogue and then update your quest.
 
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