To be fair, magic9mushroom explicitly said so: "given the ability to utilise tachyonic signals." It's a pretty hefty given, but it's a typical turn of phrase to introduce an assumption. Perhaps more common in mathematical contexts than others.
This whole thing is an experimental triumph. I'm making a note here: huge success.
Wait, so we just witnessed a second Big Bang?Am I the only one squeeing over this?
Favorite part:
The invisible, silent scream of space-time, the echoes of which are just barely detectable from over a billion light years away.
Do you have gifs for frame-dragging too?
Thanks, fixed in the original post. This is what I get for forgetting conservation of energy and only relying on vague memories of EM field multipole expansion.While it's true that gravitational radiation requires a changing quadrupole moment rather a dipole moment as electromagnetic radiation does, and this definitely affects how hard it is to produce strong waves, the gravitational wave energy is still ∝1/r² and amplitude ∝1/r as usual. The latter is what's important here, as it's directly related to the strain observed by LIGO.
Nah, the tiny part of the big band still accessible (aka the observable universe) was to this event what it was to our sun's second-per-second regular output.
If that's the case, doesn't two starships driving at 0.9c in opposite directions result in de facto FTL travel? Because if I'm understanding relativity here correctly, then from the reference frame of starship A, it looks like starship B is moving away at 1.8c...It's because of the principle of relativity. If the instantaneous signal is possible in one inertial frame, then instantaneous signaling must be possible in any other inertial frame. Thus (green signal is possible)⇒(yellow signals are possible). Of course, if you throw out the principle of relativity, you could keep causality by e.g. insisting that there is a global reference frame in which the signaling is instantaneous and no other FTL speeds are allowed.
In general, a Lorentz boost on a Minkowski plane acts like a rotation along hyperbolas with lightlike paths as their asymptotes, so you can boost any superluminal speed (including faster-than-infinite, i.e. directed below the spatial axis) into any other superluminal speed. So the principle of relativity would imply that any superluminal speed being possible implies that all of them are.
If that's the case, doesn't two starships driving at 0.9c in opposite directions result in de facto FTL travel? Because if I'm understanding relativity here correctly, then from the reference frame of starship A, it looks like starship B is moving away at 1.8c...
If that's the case, doesn't two starships driving at 0.9c in opposite directions result in de facto FTL travel? Because if I'm understanding relativity here correctly, then from the reference frame of starship A, it looks like starship B is moving away at 1.8c...
they don't have to be 9sNope. They will appear to be approaching each other at 0.9something c. Need to find the right equations for that but all you can ever do is add more 9s onto the end. That's what relativity is, you can't ever go faster than c from any perspective.
Nope. They will appear to be approaching each other at 0.9something c. Need to find the right equations for that but all you can ever do is add more 9s onto the end. That's what relativity is, you can't ever go faster than c from any perspective.
This reminds me of a more experimental proof of why 0.9[Recurring] is equal to one. No matter many nines you add, it will be less than one because one is equal to an infinite series of nines.Nope. They will appear to be approaching each other at 0.9something c. Need to find the right equations for that but all you can ever do is add more 9s onto the end. That's what relativity is, you can't ever go faster than c from any perspective.
Of course, to add infinite nines, you'd need infinitely more speed (differential), which would need infinite energy. And your frame of reference will always be finite, since your speed can only be finite without infinite energy (and even with, it could only approximate c, which is still not infinite).This reminds me of a more experimental proof of why 0.9[Recurring] is equal to one. No matter many nines you add, it will be less than one because one is equal to an infinite series of nines.
I tend not to read casual posts as I do proofs, so I read it as 'since we have tachyons, we know time travel is possible', reinforced by his use of 'demonstratably possible'. If that is a misunderstanding of @magic9mushroom, then I apologise.
Of course, to add infinite nines, you'd need infinitely more speed (differential), which would need infinite energy. And your frame of reference will always be finite, since your speed can only be finite without infinite energy (and even with, it could only approximate c, which is still not infinite).
That's the problem with dealing with infinity in physics
If that's the case, doesn't two starships driving at 0.9c in opposite directions result in de facto FTL travel? Because if I'm understanding relativity here correctly, then from the reference frame of starship A, it looks like starship B is moving away at 1.8c...
If that's the case, doesn't two starships driving at 0.9c in opposite directions result in de facto FTL travel? Because if I'm understanding relativity here correctly, then from the reference frame of starship A, it looks like starship B is moving away at 1.8c...
Sorry, fresh out.
If that's the case, doesn't two starships driving at 0.9c in opposite directions result in de facto FTL travel? Because if I'm understanding relativity here correctly, then from the reference frame of starship A, it looks like starship B is moving away at 1.8c...
That's a misunderstanding. In general, if someone tells you that they beat a fundamental principle of quantum mechanics, take it with a huge grain of salt. What's actually going on is that in the context of interferometry, the term 'standard quantum limit' refers to a limit based on statistical averaging over N particles without taking into account any quantum correlations, to give a limit of Δφ ≈ 1/√N. It is basically a shot noise model, with the 'quantum' part just recognising that the light is made of particles.My physics teacher today told us that the cool thing about this is not the gravitational waves. Those were expected. He told us the cool thing is that the accuracy of LIGO's measurements go beyond what the uncertainty principle would tell us is the limit of accuracy of position over time.
Einstein was right should be a meme. Considering how people want to prove him wrong and keep failing.
Ok, I get you. But to me it seems odd to call it that because the uncertainty principle just says that ΔNΔφ ≥ 1/2, and everything else is an assumption on the state, while the actual limit set by the uncertainty principle is smaller than the shot noise limit—and frequently called the 'Heisenberg limit' in the literature, too.That's not what I really say (or at least mean) in the rest of the quote. What we've succeeded in doing is beating what was conventionally thought to be the limit of measurement over time as one of the consequences of the uncertainty principle.