- Location
- Texas
A few concerns were brought up when the Air Tunnel seals were proposed.Could you write up the math on these by the way? I haven't gone through it myself.
- But the air it has to store on the way down is way too much! It won't be able to fit!
Our best measuring stick for storing a gas is Implosion Seals. With a radius of 1-20 m, an Implosion Seal is capable of storing (V = (4/3)πr^3) between 4.2 m^3 and 33510 m^3 of atmosphere pressure air. We'll use 33510 m^3 as our absolute maximum and aim to be well below it.
Okay, so now we have our maximum volume to store. We are currently operating under the premise that we are staying within the troposphere, so we'll use 12 km as our maximum operating height. By dividing 33510 m^3 by 12000 m, we get 2.8 m^2. So long as no one seal has an absorption area of 2.8 m^2 when dropped from <=12 km, they won't exceed our observed maximum air storage of 33510 m^3.
- Okay, so it's probably not too MUCH air, but it's going to have to absorb it too quickly! It won't be able to keep up!
For this one, we're going to have to get into the actual payload that is being dropped. The current plan is to use Hazo's Earthshaping jutsu at maximum volume (16 m^3) in order to merge sealed chunks of granite 12 km above the ground into a rectangular prism. Granite has a density of 2700 kg/m^3, so 16 m^3 of it will have a mass of 43,200 kg and be 1.67 x 1.67 x 5.74 meters.
When you don't have to worry about air resistance, you get a neat equation for finding the velocity of a free falling object after it falls d distance. (v = sqrt(2gd) ) We are, perhaps foolishly, assuming that gravity is 9.81 m/s^2. This means that after falling for 12 km, the object has a velocity of 485 m/s.
We calculated that maximum area of our seal can be 2.8 m^2, the current size of the bottom of our projectile. Since this is the absolute maximum, let's split it into 4, just to be on the safe side. This means that each seal will cover an area of 0.7 m^2. When traveling at the maximum velocity, 485 m/s, that seal would have to absorb 340 m^3/s. This is orders of magnitude less than a 20 m Implosion Seal's instantaneous storage of 33510 m^3.
- Okay, fine. It can store enough air and it can store it fast enough. How much damage does it do?
....That's a hard one. We have a mass and final velocity, so we can calculate the kinetic energy in the payload. (E = (1/2)mv^2 ) Our 43,200 kg payload traveling at 485 m/s will have 5.08e+9 Joules of kinetic energy. Is that sufficient to penetrate or damage Hidden Rock's underground areas? Only time will tell. If it requires additional energy, we can attempt to scale even higher in the atmosphere with the proper precautions.
Air density is much lower at high altitude, so the total amount of air absorbed by the seals is actually lower than calculated. This means that the area covered by one could theoretically be larger, though there are few benefits to actually doing so.